MAT10:1.1.4 Solving equations involving brackets

Solve the equation 2(x + 3) = 8

Solve the equation 3(2x  – 1) =-21

Solve the equation -2(2x – 3) = 14

Solve the equation -(3 – 4x) = -1

Solve the equation 4(3 + 2x) = -20

Solve the equation -2(5 – 2a)=-12

Solve the equation -3(2 + x)=0

Solve the equation 3(2x – 1) = 27

Solve the equation 4(1 – 2x) = -8

Solve the equation – (2 -3x) = -8

Solve the equation 2(a+2)=3(a-1)

Solve the equation 5 – 2(p + 3) = 3

S0lve the equation 3x – (4  – 3x) = -10

Solve the equation 2(m – 3) – 3(m + 2) = -14

Solve the equation -(3 – 2x) – 2(1 +3 x) = 7

The length of a rectangle A is (x + 3) cm and its width is 5 cm.  The length of another rectangle B is (2x  – 1) cm and its width is 3 cm.  Given the sum of the areas of the two rectangles is 23 cm², find the length of rectangle A.

The length of a rectangle P is (2x + 1) cm and its width is x cm.  A rectangle Q of length (x + 1) cm and width x cm is cut from the rectangle P. Given the area of the remaining shape is 225 cm², find the value of x.

A triangle has base length 8 cm and height (2x + 1) cm.  Find the height of the triangle if its area is 28 cm².

The dimensions of a cuboid are 3 cm by 4 cm by (4 – 3x) cm.  Find the value of x, if the volume of the cuboid is 120 cm³.

The length of a cube is (2x + 1) cm and its volume is 27 cm³.  Find the total surface area of the cuboid.